The image above shows current measurments with the inverter under load. Images on the right show a decoupled circuit and the ones on the left shows a circuit without that capacitor. You can see ...

The gradient of this graph is equal to the capacitance of the capacitor. \(C= \frac{Q}{V}\) And the area under the graph is the energy stored by the capacitor.

If a larger value of resistance were used with the same value of capacitance in the above circuit, then a smaller current would flow, therefore it would take longer for the capacitor to charge up ...